A) \[\sin \,(m-2n)+{{2}^{2m-n}}\]
B) \[\sin \,(2m-n)+{{2}^{(m-n)2}}\]
C) \[\sin \,(m-2n)+{{2}^{(m+n)2}}\]
D) \[\sin (2m-n)+{{2}^{2m-n}}\]
Correct Answer: D
Solution :
Given, \[f(2x+3)=\sin \,x+{{2}^{x}}\] Put \[x=2m-n\] \[\therefore \] \[f[2(2m-n)+3]=sin(2m-n)+{{2}^{2m-n}}\] \[\Rightarrow \] \[f(4m-2n+3)=sin(2m-n)+{{2}^{2m-n}}\]
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