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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    A block of mass \[2\text{ }kg\]rests on a horizontal surface. If a horizontal force of \[5\text{ }N\]is applied on the block the frictional force on, it is \[({{\mu }_{k}}=0.4,\,\,{{\mu }_{s}}=0.5)\]

    A)  \[5\,\,N\]           

    B)  \[10\,\,N\]

    C)  \[8\,\,N\]           

    D)  zero

    Correct Answer: C

    Solution :

    The frictional force F is given by \[F={{\mu }_{k}}mg\] Given, \[{{\mu }_{k}}=0.4,\,\,\,\,\,m=2kg,\,\,\,\,\,\,\,g=10m/{{s}^{2}}\] \[\therefore \] \[F=0.4\times 2\times 10\] \[F=8N\]


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