A) \[\frac{2\,m{{L}^{2}}}{3}\]
B) \[\frac{\,m{{L}^{2}}}{12}\]
C) \[\frac{\,m{{L}^{2}}}{6}\]
D) None of these
Correct Answer: C
Solution :
\[I={{I}_{x}}+{{I}_{y}}=\frac{m{{L}^{2}}}{12}+\frac{m{{L}^{2}}}{12}=\frac{m{{L}^{2}}}{6}\]
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