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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    The second overtone of an open pipe is in resonance with the first overtone of a closed pipe of length \[2\,m\]. Length of the open pipe is

    A)  \[4\,m\]          

    B)  \[2\,m\]

    C)  \[8\,m\]          

    D)  \[1\,m\]

    Correct Answer: A

    Solution :

    Second overtone of open pipe of length I is \[{{n}_{0}}=\frac{v}{2l}\] ??(i) First overtone of a closed pipe is \[{{n}_{c}}=\frac{v}{4l}=\frac{v}{4\times 2}\] ?..(ii) Equating Eqs. (i) and (ii), we get \[\frac{v}{2l}=\frac{v}{8}\] \[\Rightarrow \] \[l=4\,m\]


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