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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    A battery of emf \[2\text{ }V\]and internal resistance  \[0.1\Omega \] is being charged by a current of \[~5\text{ }A\]. The potential difference between the terminals of the battery is

    A)  \[2.5\text{ }V\]          

    B)  \[1.5\text{ }V\]

    C)  \[0.5V\]          

    D)  \[1\,\,V\]

    Correct Answer: A

    Solution :

    When r is internal resistance of the battery and i the charging current, then \[V=E+ir\] \[V=2+5\times 0.1=2.5V\]


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