A) \[C{{H}_{3}}Br,\bar{O}H\]
B) \[C{{H}_{3}}Br\]only
C) \[~\bar{O}H\] only
D) \[~C{{H}_{3}}Br,C{{H}_{3}}OH\]
Correct Answer: A
Solution :
\[C{{H}_{3}}Br+O{{H}^{-}}\xrightarrow{{}}C{{H}_{3}}OH+B{{r}^{-}}\] This reaction proceeds by \[{{\text{S}}_{\text{.N}}}\text{2}-\]mechanism Rate \[\propto \][substrate] [nucleophile] Rate \[\propto [C{{H}_{3}}Br][O{{H}^{-}}]\]
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