A) 2.6
B) 1.71
C) 1.4
D) 0.95
Correct Answer: B
Solution :
\[{{C}^{4-}},{{N}^{3-}}\]and\[{{O}^{2-}}\]are isoelectronic species. The ionic radius of isoelectronic species decreases with increase the nuclear charge. Hence, the order of ionic radius is \[\begin{align} & \text{Species:}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{C}^{4-}}\,>\,\,\,\,{{N}^{3-}}>\,\,{{O}^{2-}} \\ & \text{Ionic}\,\text{radii(}\overset{\text{o}}{\mathop{\text{A}}}\,\text{)}\,\,\,\,\,\text{2}\text{.60}\,\,\,\,\,\text{1}\text{.71}\,\,\,\,\,\,\text{1}\text{.40} \\ \end{align}\]
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