2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    \[\text{KMn}{{\text{O}}_{\text{4}}}(mol\,wt.=158)\]oxidizes oxalic acid in acid medium to \[\text{C}{{\text{O}}_{\text{2}}}\]and water as follows \[5{{C}_{2}}O_{4}^{2-}+2MnO_{4}^{-}+16{{H}^{+}}\to 10C{{O}_{2}}+2M{{n}^{2+}}\]\[\text{+}\,\,\text{8}{{\text{H}}_{\text{2}}}\text{O}\] What is the equivalent weight of\[\text{KMn}{{\text{O}}_{\text{4}}}\]?

    A)  158         

    B)  31.6

    C)  39.5         

    D)  79 

    Correct Answer: B

    Solution :

     \[5{{C}_{2}}O_{4}^{2-}+\overset{+\,\,7}{\mathop{2MnO_{4}^{-}}}\,+16{{H}^{+}}\to 10C{{O}_{2}}+2M{{n}^{2+}}\] \[+\,8{{H}_{2}}O\] Equivalent weight \[=\frac{\text{molecular}\,\text{weight}}{\text{change}\,\text{in}\,\text{oxidation}\,\text{number}}\] \[=\frac{158}{5}=31.6\]


You need to login to perform this action.
You will be redirected in 3 sec spinner