A) 0.5
B) 0.2
C) 0.1
D) 0.301
Correct Answer: C
Solution :
\[\because \]\[pH=2\] \[\therefore \] \[[{{H}^{+}}]={{10}^{-2}}\] \[[{{H}^{+}}]=N.\alpha \] \[{{10}^{-2}}=0.1\times \alpha \] \[\alpha =\frac{{{10}^{-2}}}{0.1}\] \[\alpha =0.1\]
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