A) \[2.01\times {{10}^{11}}s\]
B) \[2.01\times {{10}^{13}}s\]
C) \[8.08\times {{10}^{13}}\,s\]
D) \[16.04\times {{10}^{11}}\,s\]
Correct Answer: B
Solution :
For two-third of a reaction: \[{{[A]}_{0}}=a,[A]=a-\frac{2}{3}a=\frac{a}{3}\] \[{{t}_{2/3}}=\frac{2.303}{k}\log \frac{{{[A]}_{0}}}{[A]}\] \[=\frac{2.303}{k}\log \frac{a}{\frac{a}{3}}=\frac{2.303}{k}\log 3\] \[{{t}_{2/3}}=\frac{2.303\times 0.4771}{5.48\times {{10}^{-14}}}=2.01\times {{10}^{13}}\,s\]
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