A) \[\{n\pi :n\in I\}\]
B) \[\{n\pi /2:n\in I\}\]
C) \[\{n\pi /k:n\in I\}\]
D) \[\{n\pi /2k:n\in I\}\]
Correct Answer: C
Solution :
Given, \[\tan \,(k+1)\theta =tan\theta \] \[\Rightarrow \] \[(k+1)\theta =n\pi +\theta \] \[\Rightarrow \] \[k\theta =n\pi \] \[\Rightarrow \] \[\theta =\frac{n\pi }{k}\] \[\therefore \] \[\theta \in \left\{ \frac{n\pi }{k}:n\in I \right\}\]
You need to login to perform this action.
You will be redirected in
3 sec
