2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    Foot of the perpendicular from \[(-2,1,4)\] to a plane is  \[(3,1,2)\], then the equation of the plane is

    A)  \[4x-2y=11\]

    B)  \[5x-2y=10\]

    C)  \[5x-2z=11\]

    D)  \[5x+2z=11\]

    Correct Answer: C

    Solution :

    Given \[A(3,1,2)\] be the foot of the perpendicular from \[B(-2,1,4)\] on the plane, then direction ratios of BA, the normal to the plane are \[(3+2,1-1,2-4)=(5,0,-2)\] Also, it passes through \[A(3,1,2),\] then equation of the plane is \[5(x-3)+0(y-1)-2(z-2)=0\] \[\Rightarrow \] \[5x-15+0-2z+4=0\] \[\Rightarrow \] \[5x-2z=11\]


You need to login to perform this action.
You will be redirected in 3 sec spinner