A) \[36\text{ }kg-wt\]
B) \[27\text{ }kg-wt\]
C) \[18\text{ }kg-wt\]
D) \[72\text{ }kg-wt\]
Correct Answer: A
Solution :
Fundamental frequency, \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] ie, \[n\,\propto \sqrt{T}\] \[\therefore \] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\Rightarrow \] \[\frac{450}{900}=\sqrt{\frac{9}{{{T}_{2}}}}\] \[{{T}_{2}}=36\,kg-wt\]
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