A) zero
B) twice as that on the surface
C) half of that on the surface
D) same as that on the surface
Correct Answer: D
Solution :
Electric potential of charged, spherical shell \[V=\frac{q}{4\pi {{\varepsilon }_{0}}R}\] \[[0\le r\le R]\] \[\therefore \] Electric potential at centre = Electric potential on the surface. .
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