A) + 3
B) + 4
C) + 5
D) + 6
Correct Answer: A
Solution :
Oxidation state of Cr in \[\text{C}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]is \[C{{r}_{2}}{{O}_{3}}\] \[2x+(-2)\,3=0\] \[2x-6=0\] \[2x=6\] \[x=+\,3\]
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