A) \[\sqrt{6}\]
B) \[\sqrt{3}\]
C) \[\sqrt{5}\]
D) \[\sqrt{7}\]
Correct Answer: B
Solution :
Length of the diagonal \[AB=\sqrt{{{(1-2)}^{2}}+{{(-2+3)}^{2}}+{{(3-5)}^{2}}}\] \[=\sqrt{1+1+4}=\sqrt{6}\] Now. \[A{{C}^{2}}+B{{C}^{2}}=A{{B}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}+{{x}^{2}}={{(\sqrt{6})}^{2}}\] \[\Rightarrow \] \[2{{x}^{2}}=6\] \[\Rightarrow \] \[{{x}^{2}}=3\] \[\Rightarrow \] \[x=\sqrt{3}\] (\[\because \] length cannot be negative)You need to login to perform this action.
You will be redirected in
3 sec