A) \[\alpha x+\beta y+\gamma z=p\]
B) \[\frac{x}{\alpha }+\frac{x}{\beta }+\frac{z}{\gamma }=p\]
C) \[2\alpha x+2\beta y+2\gamma z={{p}^{2}}\]
D) \[\alpha x+\beta y+\gamma z={{p}^{2}}\]
Correct Answer: A
Solution :
Equation of plane is \[\vec{r}\,.\hat{n}=d\] Where d is the perpendicular distance of the plane from origin. \[\Rightarrow \] \[\alpha x+\beta y+\gamma z=0\]
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