J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    A random variable X has the following probability distribution
    \[X(={{x}_{i}})\] \[1\] \[2\] \[3\] \[4\]
    \[P(X={{x}_{i}})\] \[k\] \[2k\] \[3k\] \[4k\]
    Then, the mean of X is

    A)  \[3\]             

    B)  \[1\]

    C)  \[4\]            

    D)  \[2\]

    Correct Answer: A

    Solution :

    Sum of probability distribution is 1. \[\therefore \] \[k+2k+3k+4k=1\] \[\Rightarrow \] \[10k=1\] \[\Rightarrow \] \[k=\frac{1}{10}\] Now, mean \[\bar{x}=k\times 1+2k\times 2+3k\times 3+4k\times 4\] \[=k+4k+9k+16k=30k\] \[=30\times \frac{1}{10}=3\]


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