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J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    A stress of \[3.18\times {{10}^{8}}\,N-{{m}^{-2}}\] is applied to a steel rod of length 1 m along its length. Its Young's modulus is \[2\times {{10}^{11}}\text{ }N-{{m}^{-2}}\]. Then, the elongation produced in the rod (in mm) is

    A)  \[3.18\]           

    B)  \[6.36\]

    C)  \[5.18\]           

    D)  \[1.59\]

    Correct Answer: D

    Solution :

    \[Y=\frac{Fl}{A\Delta l}\] \[\Rightarrow \] \[\Delta l=\frac{Fl}{AY}\] \[\therefore \] \[\Delta l=\frac{3.18\times {{10}^{8}}\times 1}{2\times {{10}^{11}}}\] \[=1.59\times {{10}^{-3}}m\] \[=1.59\,mm\]


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