A) \[{{n}_{E}}<<{{n}_{H}}\]
B) \[{{n}_{E}}>>{{n}_{H}}\]
C) \[{{n}_{E}}={{n}_{H}}\]
D) \[{{n}_{E}}={{n}_{H}}=0\]
Correct Answer: B
Solution :
In an n-type semiconductor, majority charge carriers are electrons and minority charge carriers are holes. Therefore, \[{{n}_{g}}>>{{n}_{H}}\]
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