A) + 2
B) + 4
C) 0
D) + 3
Correct Answer: D
Solution :
The general electronic configuration of lanthanides is \[[Xe](n-2){{f}^{1-14}}(n-1)\,{{d}^{1}}n{{s}^{2}}\] \[\because \]After the loss of both of the 65 electrons and also the solitary d electrons, the lanthanoids gain stable configurations. \[\therefore \]\[\text{+}\,\,\text{III}\,\text{(+}\,\text{3)}\] oxidation state is most common among lanthanides.
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