A) 0.1 M glucose
B) \[0.1\text{ }M\text{ }BaC{{l}_{2}}\]
C) \[\text{ }\!\!~\!\!\text{ 0}\text{.1 M MgS}{{\text{O}}_{\text{4}}}\]
D) \[\text{ }\!\!~\!\!\text{ 0}\text{.1 NaCl}\]
Correct Answer: B
Solution :
Lowering of vapour pressure is a colligative property \[ie,\]depends only upon the number of particles of solute and not on the nature of solute. \[\because \]\[0.1\,M\,\text{glucose}\xrightarrow{{}}\text{remains}\,\text{undissociated}\] \[0.1\,M\,BaC{{l}_{2}}\xrightarrow{{}}B{{a}^{2+}}+2C{{l}^{-}}\Rightarrow 3\,ions\] \[0.1\,M\,MgS{{O}_{4}}\xrightarrow{{}}M{{g}^{2+}}+SO_{4}^{2-}\Rightarrow 2\,ions\] \[0.1\,M\,BaC{{l}_{2}}\] gives maximum number of particles, hence it exhibits maximum lowering of vapour pressure.
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