A) CO, NO
B) Np.CO
C) \[{{N}_{2}}O,C{{O}_{2}}\]
D) \[~C{{O}_{2}},N{{O}_{2}}\]
Correct Answer: C
Solution :
Rate of diffusion depends upon the molecular masses of gases. Therefore, the gases which have equal molecular mass, have equal rates of diffusion. \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] Molecular mass of\[{{N}_{2}}O=28+16=44\] Molecular mass of\[C{{O}_{2}}=12+32=44\] \[\therefore \] \[\frac{{{r}_{{{N}_{2}}O}}}{{{r}_{C{{O}_{2}}}}}=1\] \[\therefore \] \[{{r}_{{{N}_{2}}O}}={{r}_{C{{O}_{2}}}}\]
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