J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    If \[\vec{a},\,\,\vec{b}\,\] are  any two vectors,  then \[(2\vec{a}+3\vec{b})\times (5\vec{a}+7\vec{b})+\vec{a}\times \vec{b}\] is equal to

    A)  \[\vec{0}\]

    B)  \[0\]

    C)  \[\vec{a}\times \vec{b}\]

    D)  \[\vec{b}\times \vec{a}\]

    Correct Answer: A

    Solution :

    \[(2\vec{a}+3\vec{b})\times (5\vec{a}+7\vec{b})+\vec{a}\times \vec{b}\] \[=10(\vec{a}\times \vec{a})+14(\vec{a}\times \vec{b})+15(\vec{b}\times \vec{a})\] \[+21(\vec{b}\times \vec{b})+\vec{a}\times \vec{b}\] \[=\vec{0}+14(\vec{a}\times \vec{b})-15(\vec{a}\times \vec{b})+\vec{0}+\vec{a}\times \vec{b}\] \[=\vec{0}\]


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