A) \[100\text{ }m\]
B) \[\text{25 }m\]
C) \[\text{200 }m\]
D) \[\text{75 }m\]
Correct Answer: B
Solution :
\[{{R}_{\max }}=\frac{{{u}^{2}}}{g}=100\,m\] The range of the projectile is maximum for the angle of projection \[\theta ={{45}^{o}}\]. When the range is maximum the height attained by a projectile is, \[H=\frac{{{u}^{2}}}{4\,g}=\frac{100}{4}=25\,m\]
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