J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    Three charges \[-q,\] \[+Q\] and \[-q\] are placed in a straight line as shown. If the total potential energy of the system is zero, then the ratio \[\frac{q}{Q}\]is

    A)  \[2\]

    B)  \[5.5\]

    C)  \[4\]

    D)   \[1.5\]

    Correct Answer: C

    Solution :

    Potential energy of the system \[\frac{-kqQ}{x}-\frac{kQq}{x}+\frac{k{{q}^{2}}}{2x}=0\] \[\Rightarrow \] \[\frac{-4kqQ+k{{q}^{2}}}{2x}=0\] \[\Rightarrow \] \[k{{q}^{2}}=4kQq\] \[\frac{q}{Q}=4\]


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