J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    The masses of two particles having same kinetic energies are in the ratio\[1:2\]. Then their de-Broglie wavelengths are in the ratio

    A)  \[2:1\]

    B)  \[1:2\]

    C)  \[\sqrt{2}:1\]          

    D)  \[\sqrt{3}:1\]

    Correct Answer: C

    Solution :

    de-Broglie wavelength \[\lambda =\frac{h}{\sqrt{2\,mE}}\] or \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\] [As h is constant and £ is same for both the     masses]                         \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\sqrt{\frac{2}{1}}\] \[\Rightarrow \] \[{{\lambda }_{1}}:{{\lambda }_{2}}=\sqrt{2}:1\]           


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