A) voltage applied to the tube
B) current in the tube
C) atomic number of target element
D) nature of gas in the tube
Correct Answer: A
Solution :
When the electron loses whole of its energy in a single collision with the atoms, an X-ray photon of maximum energy \[{{h}_{\max }}\] is emitted ie, \[\frac{1}{2}m{{v}^{2}}=eV=h{{v}_{\max }}=\frac{hc}{{{\lambda }_{\min }}}\] Minimum wavelength = cut-off wavelength of X-ray \[{{\lambda }_{\min }}=\frac{hc}{eV}=\frac{12375}{{{V}_{(in\,out)}}}\overset{\text{o}}{\mathop{\text{A}}}\,\]
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