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J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    The set of quantum numbers \[n=4,l=0\]and \[s=+\frac{1}{2}\] correspond to the most loosely bound, ground state electron of which one of the following atoms?

    A)  \[Na\]

    B) \[Cl\]

    C)  \[Cr\]

    D) \[Rb\]

    Correct Answer: C

    Solution :

     \[n=4,l=0,m=0\]and \[s=+\frac{1}{2}\]set represents that the last electron enters in a \[4s\] orbital. Among the given options, only Cr is the element, last electron of which enters in a 4s orbital. \[Cr=[Ar]\,3{{d}^{5}},4{{s}^{1}}\]


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