A) \[{{\,}_{25}}Mn\]
B) \[{{\,}_{24}}Cr\]
C) \[{{\,}_{96}}Cm\]
D) \[{{~}_{26}}Fe\]
Correct Answer: C
Solution :
The electronic configuration of the given elements is as \[_{25\text{ }}Mn=[Ar]\,3{{d}^{5}},4{{s}^{2}}\] (Five unpaired electrons) \[_{24}Cr=[Ar]\,3{{d}^{5}},4{{s}^{1}}\] (Six unpaired electrons) \[_{96}Cm=[Rn]\,5{{f}^{7}},6{{d}^{1}},7{{s}^{2}}\] (Eight unpaired electrons) \[{{\,}_{26}}Fe=[Ar]\,3{{d}^{6}},4{{s}^{2}}\] (Four unpaired electrons) Thus, \[{{\,}_{\text{96}}}\text{Cm}\]has the highest number of unpaired electrons.
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