A) \[T{{i}^{3+}}\]
B) \[N{{i}^{2+}}\]
C) \[C{{o}^{2+}}\]
D) \[M{{n}^{2+}}\]
Correct Answer: A
Solution :
Magnetic moment depends upon the number of unpaired electrons. Lower the number of unpaired electrons, least is the magnetic moment. \[T{{i}^{3+}}=[Ar]\,3{{d}^{1}}4{{s}^{0}}\](One unpaired electron) \[N{{i}^{2+}}=[Ar]\,3{{d}^{8}},4{{s}^{0}}\] (Two unpaired electrons) \[C{{o}^{2+}}=[Ar]\,3{{d}^{7}},4{{s}^{0}}\] (Three unpaired electrons) \[M{{n}^{2+}}=[Ar],3{{d}^{5}},4{{s}^{0}}\] (Five unpaired electrons) Thus, \[T{{i}^{3+}},\]due to the presence of least number of unpaired electrons, has the least magnetic moment, among the given ions.
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