A) \[CoC{{l}_{3}}.3N{{H}_{3}}\]
B) \[~CoC{{l}_{3}}.6N{{H}_{3}}\]
C) \[CoC{{l}_{3}}.4N{{H}_{3}}\]
D) \[~CoC{{l}_{3}}.5N{{H}_{3}}\]
Correct Answer: D
Solution :
Since, the coordination compound when reacts with aqueous silver nitrate solution, produces two equivalents of \[AgCl,\]the two Cl ions must be present outside the coordination sphere. Thus, the composition (formula) of the coordination compound must be \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}\]or \[CoC{{l}_{3}}.5N{{H}_{3}}\] \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}+2AgN{{O}_{3}}\xrightarrow{{}}\]\[[Co{{(N{{H}_{3}})}_{5}}Cl{{(N{{O}_{3}})}_{2}}+2AgCl\]
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