J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    The radius of gyration of a thin uniform circular disc (of radius R) about an axis passing through its centre and lying in its plane is

    A)  \[R\]               

    B)  \[\frac{R}{\sqrt{2}}\]

    C)  \[\frac{R}{4}\]               

    D)  \[\frac{R}{2}\]

    Correct Answer: D

    Solution :

    In case of a disc rotating about an axis through its centre of mass and parallel to its plane \[K=\sqrt{\frac{I}{M}}=\sqrt{\frac{\left( \frac{1}{4} \right)M{{R}^{2}}}{M}}=\frac{R}{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner