A) \[[M{{L}^{-1}}{{T}^{-3}}]\]
B) \[[M{{L}^{-1}}{{T}^{-1}}]\]
C) \[[M{{L}^{-2}}{{T}^{-1}}]\]
D) \[[ML{{T}^{-1}}]\]
Correct Answer: B
Solution :
\[F=-\eta A\frac{dv}{dx}\] \[\Rightarrow \] \[[\eta ]=[M{{L}^{-1}}{{T}^{-1}}]\]
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