A) \[4:2:1\]
B) \[2:2:1\]
C) \[1:2:4\]
D) \[1:1:1\]
Correct Answer: B
Solution :
Radius of the path \[r=\frac{\sqrt{2mK}}{qB}\] or \[r\propto \frac{\sqrt{1}}{q}\] \[{{r}_{p}}:{{r}_{d}}:{{r}_{\alpha }}=\frac{\sqrt{1}}{{{q}_{p}}}:\frac{\sqrt{1}}{{{q}_{d}}}:\frac{\sqrt{1}}{{{q}_{\alpha }}}\] \[\frac{1}{1}:\frac{1}{1}:\frac{1}{2}=2:2:1\]
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