A) \[0.15\text{ }G\]
B) \[0.15\,\sqrt{3}G\]
C) \[0.15\,\sqrt{2}G\]
D) \[~0.60\text{ }G\]
Correct Answer: D
Solution :
\[{{B}_{H}}=0.30\,G\] Angle of dip \[={{60}^{o}}\] \[B=?\] Earths magnetic field is horizontal only at the magnetic equator. At any other place, the total intensity can be resolved into horizontal component \[({{B}_{H}})\] and vertical component \[({{B}_{V}})\] Also, \[{{B}_{H}}=B\,\cos \phi \] and \[{{B}_{V}}=B\,sin\phi \] where, \[\phi \] is angle of inclination or dip \[\therefore \] \[0.30=B\,\cos \,{{60}^{o}}\] \[0.30=\frac{B}{2}\] \[\Rightarrow \] \[B=0.60\,G\]
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