J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    A   wave   motion   is   described   by \[y(x,t)=a\,\sin (kx-\omega t)\]. Then the ratio of the maximum particle velocity to the wave velocity is

    A)  \[\omega a\]

    B)  \[\frac{1}{ka}\]

    C)  \[\frac{\omega }{k}\]

    D)  \[ka\]

    Correct Answer: D

    Solution :

    Maximum particle velocity \[{{({{v}_{p}})}_{\max }}=a\omega \] and wave velocity, \[v=\frac{\omega }{k}\] \[\therefore \] Ratio \[\frac{{{({{v}_{p}})}_{\max }}}{v}=\frac{a\omega k}{\omega }=ka\]


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