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J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    Calculate the reduction potential of a half-cell containing of platinum electrode immersed in \[\text{2}\text{.0}\,\text{M}\,\text{F}{{\text{e}}^{\text{2+}}}\]and \[\text{0}\text{.02 M F}{{\text{e}}^{\text{3+}}}\text{.}\] Given \[\text{E}_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}=0.771\,V,\] \[F{{e}^{3+}}+{{e}^{-}}\xrightarrow{{}}F{{e}^{2+}}\]

    A)  0.653 V         

    B)  0.889 V

    C)  0.0653V        

    D)  2.771V

    Correct Answer: A

    Solution :

     The Nernst?s equation, for the half-cell reaction,                              \[F{{e}^{3+}}+{{e}^{-}}\xrightarrow{{}}F{{e}^{2+}}\]is \[{{E}_{F{{e}^{3+}}/F{{e}^{2+}}}}=E_{F{{e}^{3+}}/F{{e}^{2+}}}^{o}-\frac{0.0591}{1}\log \frac{[F{{e}^{2+}}]}{[F{{e}^{3+}}]}\] \[=0.771-0.0591\log \frac{2.00}{0.02}\] \[=0.771-0.0591\log {{10}^{2}}\] \[=0.771-0.0591\times 2\] \[=+\,0.653\,V\]


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