A) \[{{30}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{45}^{o}}\]
D) \[{{\tan }^{-1}}\,(2)\]
Correct Answer: B
Solution :
Given, horizontal range \[=\frac{4}{\sqrt{3}}\] (maximum height) \[\frac{{{u}^{2}}\,\sin \,\,2\alpha }{g}=\frac{4}{\sqrt{3}}.\,\frac{{{u}^{2}}\,{{\sin }^{2}}\,\alpha }{2g}\] \[\Rightarrow \] \[\frac{\sin \,2\alpha }{2\,{{\sin }^{2}}\,\alpha }=\frac{1}{\sqrt{3}}\] \[\Rightarrow \] \[\tan \,\alpha =\sqrt{3}\] \[\Rightarrow \] \[\alpha ={{60}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
