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J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    Two events A and 5 have probabilities \[0.3\] and \[0.4\] respectively. The probability that both A and B occur simultaneously is \[0.1\]. The probability that neither A nor B occur is

    A)  \[0.2\]

    B)  \[0.3\]

    C)  \[0.4\]

    D)  \[0.1\]

    Correct Answer: C

    Solution :

    \[P(A)=0.3\] \[P(B)=0.4\] \[P(A\cap B)=0.1\] \[\therefore \]   \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] \[=0.3+0.4-0.1\] \[=0.6\]


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