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J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    An LCR series circuit is under resonance. \[{{I}_{m}}\] is current amplitude, \[{{V}_{m}}\] is voltage amplitude, R is the resistance, Z is the impedance, \[{{X}_{L}}\] is the inductive reactance and \[{{X}_{C}}\] is the capacitive reactance then,

    A)  \[{{I}_{m}}=\frac{{{V}_{m}}}{Z}\]

    B)  \[{{I}_{m}}=\frac{{{V}_{m}}}{{{X}_{L}}}\]

    C)  \[{{I}_{m}}=\frac{{{V}_{m}}}{{{X}_{C}}}\]

    D)  \[{{I}_{m}}=\frac{{{V}_{m}}}{R}\]

    Correct Answer: A

    Solution :

    In LCR circuit the current \[{{I}_{m}}=\frac{{{V}_{m}}}{Z}\]


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