question_answer

The hybridization involved in\[\text{PC}{{\text{l}}_{\text{5}}}\] is

A) \[s{{p}^{3}}d\]

B) \[s{{p}^{3}}{{d}^{2}}\]

C) \[{{d}^{2}}s{{p}^{2}}\]

D) \[s{{p}^{3}}\]

Correct Answer: A

Solution :

 In \[\text{PC}{{\text{l}}_{\text{5}}}\]five chlorine atoms directly attached to central atom and it has no lone pairs and no single electrons hence\[\text{PC}{{\text{l}}_{\text{5}}}\]has\[\text{s}{{\text{p}}^{\text{3}}}\text{d}\] hybridization.