J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    A radioactive element\[_{\text{92}}^{\text{238}}\text{M}\]emits one alpha particle followed by two beta particles. Then the daughter element formed is

    A)  an isotope      

    B)  an isobar

    C)  an isotone      

    D)  an isodiaphere

    Correct Answer: A

    Solution :

     \[_{92}^{238}M\xrightarrow{-\alpha }_{90}^{234}X\xrightarrow{-\beta }_{91}^{234}Y\xrightarrow{-\beta }_{92}^{234}Z\] The atomic number of radioactive element \[(_{92}^{238}M)\] and daughter element \[(_{92}^{234}Z)\] is same hence they are isotopes.


You need to login to perform this action.
You will be redirected in 3 sec spinner