A) 4
B) 6
C) 8
D) 12
Correct Answer: A
Solution :
Zinc blende (ZnS) has fee structure. It is an ionic crystal having 4:4 coordination number. \[{{S}^{2-}}\]form fee lattice and\[\text{Z}{{\text{n}}^{\text{2+}}}\]has alternate tetrahedral voids. Hence, in zinc blende structure, the coordination number of cation \[\text{(Z}{{\text{n}}^{\text{2+}}})\]is 4.
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