A) \[10\text{ }cm\]in front of the mirror
B) \[7.5\text{ }cm\]behind the mirror
C) \[2.5\text{ }cm\]in front of the mirror
D) \[7.5\text{ }cm\]in front of the mirror
Correct Answer: D
Solution :
Here, \[f=-5\,cm\] \[u=-15\,\,cm\] \[v=?\] From the mirror formula \[\frac{1}{f}=\frac{1}{y}+\frac{1}{v}\] \[\frac{1}{-15}+\frac{1}{v}=-\frac{1}{5}\] \[\frac{1}{v}=\frac{1}{-5}+\frac{1}{15}\] \[v=-7.5m\] The image is formed at \[7.5\text{ }cm\]in front of the mirror.
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