2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2012

  • question_answer
    The equation describing the motion of a simple harmonic oscillator along the x axis is given as \[x=A\,\,\cos (\omega t+\phi ).\]. If at time \[t=0,\] the oscillator is at \[x=0\]and moving in the negative x-direction, then the phase angle \[\phi \] is

    A)  \[\frac{\pi }{2}\]

    B)  \[-\frac{\pi }{2}\]

    C)  \[\pi \]

    D)  \[0\]

    Correct Answer: A

    Solution :

    \[x=A\,\,\cos \,(\omega t+\phi )\] Let \[t=0,\,\,\,\,x=0\] \[0=\cos \phi \] \[\cos \frac{\pi }{2}=\cos \phi \] \[\theta =\frac{\pi }{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner