A) unimolecular
B) bimolecular
C) trimolecular
D) rate depends on concentration of incoming nucleophile
Correct Answer: A
Solution :
A nucleophilic substitution reaction proceeds through\[{{\text{S}}_{\text{N}}}\text{1}\]mechanism, so the reaction is unimolecular. \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,\xrightarrow{\text{Slow}}C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{+}}}}}\,}}}\,+B{{r}^{-}}\] \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{+}}}}}\,}}}\,+O{{H}^{-}}\xrightarrow{\text{Fast}}C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OH\] \[\text{Rate}\propto [{{3}^{o}}\,\text{alkyl}\,\text{halide}\,]\]
You need to login to perform this action.
You will be redirected in
3 sec
