A) \[x=1\]
B) \[x=-1\]
C) \[x=\frac{3}{2}\]
D) \[x=\frac{2}{3}\]
Correct Answer: C
Solution :
Given equation of parabola is \[{{y}^{2}}+4x+4y+2=0\] \[\therefore \] \[{{(y+2)}^{2}}+4x-2=0\] \[{{(y+2)}^{2}}=-4\,\left( x-\frac{1}{2} \right)\] It is of the form of \[{{y}^{2}}=-4AX.\] \[\therefore \] \[A=1\] \[\therefore \] Equation of directrix is \[x=A.\] \[\therefore \] \[x-\frac{1}{2}=1\] \[\Rightarrow \] \[x=\frac{3}{2}\]
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