A) \[1300\text{ }m/s\]
B) \[2600\text{ }m/s\]
C) \[1898\text{ }m/s\]
D) \[650\text{ }m/s\]
Correct Answer: C
Solution :
\[{{v}_{rms}}={{v}_{s}}\sqrt{\frac{3}{\gamma }}\] Also, \[\gamma =\frac{{{C}_{P}}}{{{C}_{V}}},R={{C}_{P}}-{{C}_{V}}\] Given, \[R=1.98cal\,\,{{K}^{-1}}mo{{l}^{-1}},\] \[{{C}_{P}}=6.84\,cal\,{{K}^{-1}}\,mo{{l}^{-1}},\] \[{{C}_{P}}=4.86\,cal\,{{K}^{-1}}\,mo{{l}^{-1}},\,\,\gamma =1.41\] \[{{v}_{rms}}=1300\sqrt{2.13}\approx 1898m/s\]
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