A) \[0.159\,\,s\]
B) \[3.14\,\,s\]
C) \[6.5\,\,s\]
D) \[6.28\text{ }s\]
Correct Answer: D
Solution :
Time period \[T=2\pi \sqrt{\frac{l}{g}}\] Given, \[g=9.8m/{{s}^{2}},l=9.8m\] \[T=2\pi \sqrt{\frac{9.8}{9.8}}=2\pi =2\times 3.14=6.28s\]
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